How to parse json data in nsstring?

Question

I am getting response form api like this.

{"token":"eyJ0eXAiOiJKV1QiLCJhbGciOiJIUzI1NiJ9.eyJlbWFpbCI6ImpvaG4uc21pdGhAZ21haWwuY29tIiwiaWQiOiI1NzFkYzI3NmU0YjA1NjVmNTcwZjM2ZGQiLCJpYXQiOjE0NjMwMjk4NDd9.yi8H75GTS-U8abcS75WcGT5ROfmM0AgCNfRIiZQzeNI","data":{"name":"John Smith","role":"driver"},"message":"success"}

But when I try to get value of token it gives me null at the same time when get value of role it give me perfect value.

Please look at my code.

NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:[NSURL URLWithString:@"http://qa.networc.in:1336/api/drivers/login"]]; NSURLSession *session = [NSURLSession sharedSession]; NSString * params =[NSString stringWithFormat:@"email=%@&password=%@&deviceId=fc2ffdf08ccf0dc912018f7232e4aa0ffcbd856ec3faf4145649f8bb281a779d",_driverNumberTextField.text,_passwordTextField.text]; NSLog(@"params %@", params); request.HTTPMethod = @"POST"; request.HTTPBody =[params dataUsingEncoding:NSUTF8StringEncoding]; NSURLSessionDataTask *task = [session dataTaskWithRequest:request completionHandler:^(NSData *data, NSURLResponse *response, NSError *error) { NSLog(@"Response:%@ %@\n", response, error); if(error == nil) { // use NSJSON Serlizeitaion and serlize your value NSString * text = [[NSString alloc] initWithData: data encoding: NSUTF8StringEncoding]; NSLog(@"Data = %@",text); id object = [NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&error]; dictionary = [[NSJSONSerialization JSONObjectWithData:data options:0 error:nil]objectForKey:@"JSON"]; NSString *temp; temp = (NSString*)[dictionary valueForKey:@"token"]; NSLog(@"temp %@", temp); dictionary = [[NSJSONSerialization JSONObjectWithData:data options:0 error:nil]objectForKey:@"data"]; Role = (NSString*)[dictionary valueForKey:@"role"]; NSLog(@"role %@", Role);

There are many post related to JSON parsing....try to find out that and don't ask similar question. — Mahendra
– Mahendra, Commented May 12, 2016 at 5:19
You have made a mistake instead of dictionary = [[NSJSONSerialization JSONObjectWithData:data options:0 error:nil]objectForKey:@"JSON"]; use dictionary = [NSJSONSerialization JSONObjectWithData:data options:0 error:nil]; — Sanman
– Sanman, Commented May 12, 2016 at 5:20
remove the objectForKey:@"JSON" part as there is no key such as"JSON". — Sanman
– Sanman, Commented May 12, 2016 at 5:26

Anbu.Karthik · Accepted Answer · 2016-05-12 05:29:59Z

you need to do like

dictionary = [NSJSONSerialization JSONObjectWithData:data options:0 error:nil]; NSString *temp = (NSString*)[dictionary valueForKey:@"token"]; NSLog(@"temp %@", temp); NSDictionary *data = [dictionary valueForKey:@"data"]; NSString *tnamemp = (NSString*)[data valueForKey:@"name"]; NSString *role = (NSString*)[data valueForKey:@"role"];

Satyanarayana · Accepted Answer · 2016-05-12 05:29:31Z

//i hope it will work for u

 NSMutableDictionary *dic= [NSJSONSerialization JSONObjectWithData:data options:NSJSONReadingMutableContainers error:nil]; NSString *strToke = [dic valueForKey:@"token"];

ChintaN -Maddy- Ramani · Accepted Answer · 2016-05-12 05:33:26Z

NSJSONSerialization will return dictionary so you don't need to take objectForKey:@"JSON"

replace

dictionary = [[NSJSONSerialization JSONObjectWithData:data options:0 error:nil]objectForKey:@"JSON"];

with

dictionary = [NSJSONSerialization JSONObjectWithData:data options:0 error:nil];

Suggestion : Do not parse dictionary again just to retrieve different keys from same dictionary. Use same dictionary.

NSString *token = dictionary[@"token"]; NSString *role = dictionary[@"data"][@"role"]; NSString *name = dictionary[@"data"][@"name"];

Dinesh · Accepted Answer · 2016-05-12 05:28:02Z

Please try out the below code: The problem is here:

dictionary = [[NSJSONSerialization JSONObjectWithData:data options:0 error:nil]objectForKey:@"JSON"];

try out the below code. Hope this helps!

NSError *error = nil; NSDictionary *responseObj = [NSJSONSerialization JSONObjectWithData:jsonData options:0 error:&error]; if(! error) { NSLog(@"responseObj : %@",responseObj); NSString *token = [responseObj valueForKey:@"token"]; NSDictionary *dataDic = [responseObj valueForKey:@"data"]; NSString *role = [dataDic valueForKey:@"role"]; NSString *name = [dataDic valueForKey:@"name"]; } else { NSLog(@"Error in parsing JSON"); }

Bhavi Lad · Accepted Answer · 2016-05-12 06:20:04Z

There is problem with fetching keys Try this,

 NSDictionary *dataDictionary = [NSJSONSerialization JSONObjectWithData:data options:0 error:nil]; NSString *strToken = (NSString*)[dataDictionary valueForKey:@"token"]; NSLog(@"Token %@", strToken); NSString *strName = (NSString*)[[dataDictionary valueForKey:@"data"] valueForKey:@"name"]; NSString *strRole = (NSString*)[[dataDictionary valueForKey:@"data"] valueForKey:@"role"];

Nazik · Accepted Answer · 2016-05-12 07:31:42Z

-1

Print out single values and check. Access array $arr["token"]

edited May 12, 2016 at 7:31

Nazik

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answered May 12, 2016 at 5:22

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1 Comment

sandeep tomar Over a year ago

sir i think its in dictionary form not in array?

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