Something like this, I'd like to see the full syntax.
Pseudo Code:
var = user_input if var > 5: output = 'var > 5' else: output = 'var < 5' 
6 Answers
How about something along the lines of:
#include <stdio.h> #include <string.h> int main (void) { int var; char buff[100]; printf ("Enter number> "); fflush (stdout); if (fgets (buff, sizeof(buff), stdin) == NULL) { printf ("\nfgets() failed\n"); return 1; } if (sscanf (buff, "%d", &var) != 1) { printf ("\nsscanf() failed\n"); return 1; } if (var > 5) printf ("%d is greater than 5\n", var); else printf ("%d is less than 6\n", var); return 0; } with a couple of test runs:
pax> testprog Enter number> 99 99 is greater than 5 pax> testprog Enter number> -5 -5 is less than 6 
5 Comments
rectangletangle
What about if 'var' was a user input?
John Kugelman
I'll +2 you if you add
fflush(stdout). Since you're taking such pains to write this robustly. :-)
Jonathan Leffler
@John: why? When the program exits, the standard I/O streams are automatically flushed.
John Kugelman
@Jonathan After the prompt is printed, I mean, since it doesn't end with a newline.
John Kugelman
OK. I'm going to need somebody who doesn't like this answer to +1 it for me, if you don't mind.
Hope this will help you get started .
Comments
This seems to correspond to what you'd like:
int var; scanf("%d", &var); if (var > 5) printf("var > 5\n"); else printf("var <= 5\n"); With caveats about using scanf() - I generally don't like it for resilient code, but it gives a minimal answer swiftly.
You'd have to wrap it in a main() and #include <stdio.h> to make it executable:
#include <stdio.h> int main() { int var; scanf("%d", &var); if (var > 5) printf("var > 5\n"); else printf("var <= 5\n"); return 0; } answered Sep 16, 2010 at 4:18
Jonathan Leffler
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Comments
In addition to the other two answers, there's always the ternary operator ?: which can be used like this:
printf("var %s 5\n", var > 5 ? ">" : "<="); 
Comments
if(condition) doThis(); else doThat(); It's pretty much what you've got there. Your example:
if(var > 5) output = "var > 5"; else output = "var < 5"; The only difference is that you need semicolons after the statements and parentheses around the conditional expression, and the colons are not required.
You can also use curly braces to denote a block of commands to execute given a certain condition. When there's only one line being executed, however, the braces are not necessary. But this is equivalent to:
if(var > 5) { output = "var > 5"; } else { output = "var < 5"; } You can have braces just after the if or just after the else, or both, or neither. Remember, though, that with multiple statements the braces are required.
It's also worth noting that the line breaks are optional. This could be written
if(var > 5) output = "var > 5"; else output = "var < 5"; Or even
if(var > 5) output = "var > 5"; else output = "var < 5"; But this code is far less readable. The first and second forms are better practice.
Comments
char var = getchar(); if (atoi(var) > 5) { printf("var > 5 \n"); } else { printf("var < 5 \n"); } 
varis equal to 5.