Time formatting strings in Python

As others have pointed out in comments, it's unclear what the right answer is for some inputs (e.g. 1234, which my code would say is 00:12:34). I also decided that 02:59:59 is a better answer than 2:59:59, given the desire to get 00:00:00.

So here's my code, which deals with all of the above inputs correctly, modulo the 2:59:59 variation I chose:

import re def convert(numeric_time): return ':'.join(re.findall('..', str(numeric_time).zfill(6))) times = (212812, 218654, 232527, 235959, 0, 181240, 25959, 153834) correct_answers = ['21:28:12', '21:86:54', '23:25:27', '23:59:59', '00:00:00', '18:12:40', '02:59:59', '15:38:34'] answers = map(convert, times) for answer, correct_answer in zip(answers, correct_answers): assert answer == correct_answer, '{} != {}'.format(answer, correct_answer) 

UPDATE

Since some people object to the regular expression, here's a similar version that doesn't rely on it:

def convert(numeric_time): padded_time = str(numeric_time).zfill(6) return ':'.join(padded_time[i:i+2] for i in range(0, len(padded_time), 2)) 

Well since we're making up answers here's a "solution" that doesn't use regexes:

In [3]: def weird_time_format(fmt): ...: fmt = str(fmt) ...: hours = fmt[:2].ljust(2, '0') ...: mins = fmt[2:4].ljust(2, '0') ...: secs = fmt[4:6].ljust(2, '0') ...: return ':'.join((hours, mins, secs)) ...: In [4]: weird_time_format(212812) Out[4]: '21:28:12' 

This takes advantage of the fact that string slices are nice about out-of-bound indexes and return an empty string rather than throwing an error:

In [1]: ''[1:2] Out[1]: '' In [2]: ''[1:2].ljust(2, '0') Out[2]: '00' 

Here's the results for your example input:

In [5]: example_input = (212812, 218654, 232527, 235959, 0, 181240, 25959, 153834) In [6]: tuple(map(weird_time_format, example_input)) Out[6]: ('21:28:12', '21:86:54', '23:25:27', '23:59:59', '00:00:00', '18:12:40', '25:95:90', '15:38:34') 

And since I brought it up, what it does to 1234:

In [7]: weird_time_format(1234) Out[7]: '12:34:00' 

OK, I felt (a little) bad for being facetious. If you're genuinely interested in this approach, this will work better and is more in line with the other answer's output:

In [3]: def weird_time_format(fmt): ...: fmt = str(fmt).rjust(6, '0') ...: return ':'.join((fmt[:2], fmt[2:4], fmt[4:6])) 

Here is another attempt.

The basic concept is adding 0 if input string length less than 6.

a = (212812, 218654, 232527, 235959, 0, 181240, 25959, 153834) input_list = map(str,a) for input in input_list: if len(input) != 6: input = ''.join(['0' for i in range((6 - len(input)))]+list(input)) print ':'.join([input[i:i+chunk_size] for i in range(0,len(input),len(input)/3)]) 

Result

21:28:12 21:86:54 23:25:27 23:59:59 00:00:00 18:12:40 02:59:59 15:38:34 

Hope this helps:

data = (212812, 218654, 232527, 235959, 0, 181240, 25959, 153834) time = map(str, data) #int to string def conv(time_array): for t in time_array: if(len(t) != 6): t = str(t.zfill(6)) #filling 0's if less than 6 print ':'.join(t[i:i + 2] for i in range(0, len(t), 2)) #adding ':' conv(time) 

OUTPUT Using some test data

test = (1234, 23, 133, 6) 00:12:34 00:00:23 00:01:33 00:00:06