Why there is difference in ascii values of different compiler

Question

The code gives different outputs in gcc and in turbo c compiler. Why there is difference between ascii values in these compiler.

#include <stdio.h> int main() { int n=1; while (n<70){ printf("Ascii value is %c\n",n); n++; } return 0; }

The above program gives different outputs for values, say from 1 - 16 or something like that in gcc and in turbo c. Why is it so?

The first 32 "characters" are not actually printable, what will be printable will depend on environment. I recommend you check an ASCII table to see which characters are actually printable. Or use the standard isprint function. — Some programmer dude
– Some programmer dude, Commented Jul 2, 2016 at 14:04

Cody Gray · Accepted Answer · 2016-07-03 06:34:42Z

7

It's not the compiler, it's the console that displays those glyphs differently (the first 32 characters are non-printable). Glyphs 32 through 126 are guaranteed identical in all cases, though.

edited Jul 3, 2016 at 6:34

Cody Gray♦

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answered Jul 2, 2016 at 14:06

Paul Stelian

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4 Comments

Lightness Races in Orbit Over a year ago

This. Turbo C runs on a DOS emulator so this is almost certainly about output encoding.

Tom Blodget Over a year ago

Yes, and it almost certainly is not ASCII. Run chcp to find out what the terminal is using. (@Paul, CP437 does have printable characters <32.)

Paul Stelian Over a year ago

Yes I've seen VGA characters and even \n has an associated glyph instead of being newline (it becomes newline later)

Paul Stelian Over a year ago

And characters below 32 are nonprintable. While the console does display them, it's their choice entirely on how to represent them.

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