Hi am new to Visual C++, Could Someone please explain what ConfParams() declared in a structure does
__declspec(align(BYTE)) struct ConfParams { BOOL m_timeout; DOUBLE m_caution; ConfParams(); } 
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2 Answers
Could Someone please explain what ConfParams() declared in a structure does
It's a constructor declaration.
In C++ other than default accessibility level struct and class are equivalent. struct by default has public members, class by default has private members.
I'm not clear why your subject references __declspec but if that's what you want to know about see here.
Member functions have no alignment only the data is affected.
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yoshi99
Thanks, I was confused in seeing a constructor being defined in a struct. Wasn't quite sure if it had something to do with __declspec.
google says
http://msdn.microsoft.com/en-US/library/83ythb65%28v=VS.80%29.aspx
"Use __declspec(align(#)) to precisely control the alignment of user-defined data (for example, static allocations or automatic data in a function)"
It will make the compiler start every instance on a byte boundary. Without it instances would have been aligned on the machines natural boundary - which would probably be 4 bytes.
