How to skip the first n item(s) of an iterator in Rust?

Question

When iterating over arguments (for example) thats the most straightforward way to skip the first N elements?

eg:

use std::env; fn main() { for arg in env::args() { println!("Argument: {}", arg); } }

I tried env::args()[1..] but slicing isn't supported.

Whats the simplest way to skip the first arguments of an iterator?

ideasman42 · Accepted Answer · 2016-08-08 10:22:35Z

Turns out the .skip() method can be used, eg:

use std::env; fn main() { for arg in env::args().skip(1) { println!("Argument: {}", arg); } }

byronodmon · Accepted Answer · 2022-04-28 08:39:45Z

4

You could also do something like

 fn main() { let args: Vec<String> = env::args().collect(); for x in &args[1..] { println!("{:?}", x); } }

answered Apr 28, 2022 at 8:39

byronodmon

491 bronze badge

2 Comments

ryanwebjackson Over a year ago

Can you add a brief explanation of this solution (and how it compares to other answers)?

SaiBorg Over a year ago

The question posted is very specific to iterators and how to skip n elements while using an iterator. This answer collects the iterator into a collection and then slices into it, solves the problem, but not specifically with iterators i.e. without collecting. The top answer is correct and should have been the accepted answer.

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