Returning index of an array based on mixture of values(integer,string) or (integer,float)

Question

Hi I am trying to find a index for a number in percentage and integer array. Say arraynum = ['10%','250','20%','500'] and user sends a value 15%,in which range does this number resides? I could find index for a integer number using this code

 function test(number, ranges) { for (var i = 0; i < ranges.length; ++i) { if (number < ranges[i]) { return i; } } } var ranges = [2000, 4000, 6000, 999999]; console.log(test(1710, ranges));

Now I have mixture of integer and percentage value inside a array and number that a user pass to this function can be a integer,decimal or percentage How to find in which index does the given number resides? Should I convert all value in the mixture array to some format? How to do this? Can someone please help me with this? Thanks in advance.

Why are you doing this number < ranges[i]? I thought you want to compare if it is that number that the user inputted. — Rax Weber
– Rax Weber, Commented Oct 9, 2016 at 5:08
I need to do two steps like compare a number with given array if not find in which range the number is in and get it index. @RaxWeber — Anu
– Anu, Commented Oct 9, 2016 at 5:27
my question is that only is there any fixed range Don't tell (0,99999) but some meaningful range based on your functionality? — Aravind
– Aravind, Commented Oct 9, 2016 at 5:50

castletheperson · Accepted Answer · 2016-10-09 05:08:41Z

1

Use parseFloat() to get the floating-point value of a string. You can use the fact that it only parses up until the first non-numeric character in the string in order to ignore the %.

Here is an implementation using Array#findIndex from ES6.

function test(number, ranges) { var num = parseFloat(number); return ranges.findIndex(function(element) { return num === parseFloat(element); }); }

answered Oct 9, 2016 at 5:08

castletheperson

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7 Comments

thesublimeobject Over a year ago

I would be careful with findIndex if you aren't using a polyfill as it isn't support very well in browsers yet. Perhaps it might be better to use the [odash version: lodash.com/docs/4.16.4#findIndex

castletheperson Over a year ago

@thesublimeobject Right, the bulk of my answer is just parseFloat. They can do whatever they want for finding the index. Their loop would be fine even.

thesublimeobject Over a year ago

oh for sure. No issue with the answer whatsoever. Just wanted to point that out incase they didn't realize.

Anu Over a year ago

Thank you.I tried with this and getting -1 as index here is a fiddle jsfiddle.net/anusibi/Lvsvw6mn/5 @4castle

castletheperson Over a year ago

@Anu Is the data sorted? It's unclear to me what your input and output is meant to represent.

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Damilola · Accepted Answer · 2016-10-09 05:53:30Z

1

You might restructure your code like so

arraynum = ['10%','250','20%','500']; function test(value, arr) { return arr.indexOf(value.toString()); } test("10%", arraynum); // 0 test("500", arraynum); // 3

edited Oct 9, 2016 at 5:53

answered Oct 9, 2016 at 5:13

Damilola

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9 Comments

Anu Over a year ago

Does this gives me index for decimal,integer and percentage values? @Damilola

Damilola Over a year ago

Yes, I believe it should give you the first matched index for either integer or percentage values. It should be agnostic of the original value type since the value has been converted to string.

Anu Over a year ago

I tried with this and I am getting -1. Can you please see my edits in my question. @Damilola

Damilola Over a year ago

See my edited answer. You should get correct index for existing element and -1 if element is not found

Anu Over a year ago

Thats working. But @Damilola user can give any input like test('25%', arraynum) or test('200', arraynum) for this I am getting index -1. Am I not clear?

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Aravind · Accepted Answer · 2016-10-09 07:46:49Z

Checking condition for mixture of values with one single input is little tricky and you need to go for JSON array. Please run

var array_of_elements = [{ "Price": 250, "Percentage": "10" }, { "Price": 500, "Percentage": "25" }, { "Price": 750, "Percentage": "50" }, { "Price": 1000, "Percentage": "75" }]; function test(number_or_percent, array) { for (var i = 0; i < array.length; ++i) { if (number_or_percent.charAt(number_or_percent.length - 1) == "%") { if (parseInt(array[i].Percentage) > parseInt(number_or_percent.slice(0, ((number_or_percent.length) - 1)))) { return i; } } else { if (array[i].Price > parseInt(number_or_percent)) { return i; } } } } console.log(test('100', array_of_elements)); console.log(test('30%', array_of_elements));

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