how to create a php ternary expression containing only if statement

Question

How can I create a php ternary expression containing just if statement without the else part? This is what I tried :

$vn = condition ? expression1 ;

And this is what I'm trying to achieve

if(condition) { $vn = expression1; }

to

$vn = condition ? expression1 ;

Bart Friederichs · Accepted Answer · 2016-10-12 19:45:15Z

3

You could use the same variable in the else part:

$vn = condition ? expression1 : $vn ;

Note this creates a notice if $vn was not used before.

answered Oct 12, 2016 at 19:45

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2 Comments

You could use @$vn in the else part to prevent the notice.

@Barmar yes. But in fact you should initialise $vn first. Suppressing notices, warnings and errors is never a good idea.

The One and Only ChemistryBlob · Accepted Answer · 2016-10-12 19:53:44Z

If you are using PHP 7, you may want to consider the Null Coalescing Operator.

In certain cases, the syntax is similar to what you seem to be looking for:

$email = $_POST['email'] ?? 'none'; // is the same as: $email = isset($_POST['email']) ? $_POST['email'] : 'none';

JOUM · Accepted Answer · 2016-10-12 19:55:03Z

(condition) AND ($vn = expression1);

works too.

And only as info:

$v = condition?:expression1

is also possible, here the condition (in case) is parsed to $v