I am trying to implement the following calculation within a Bash script using "bc" but the "scale" option is producing an incorrect result with 2 additional zeros at the end, which means that I am having to trim it manually (ugly).
Calculation:
((2592000-239)÷2592000)×100
Expected result: 99,990779321 (But I would like to show only 2 decimal places)
In Bash:
echo "scale=2; ((2592000-239)/2592000)*100" | bc 99.00 echo "scale=3; ((2592000-239)/2592000)*100" | bc 99.900 echo "scale=4; ((2592000-239)/2592000)*100" | bc 99.9900 echo "scale=5; ((2592000-239)/2592000)*100" | bc 99.99000 echo "scale=8; ((2592000-239)/2592000)*100" | bc echo "scale=8; ((2592000-239)/2592000)*100" | bc 99.99077900 echo "scale=10; ((2592000-239)/2592000)*100" | bc 99.9907793200 According to the man page:
NUMBERS The most basic element in bc is the number. Numbers are arbitrary precision numbers. This precision is both in the integer part and the fractional part. All numbers are represented internally in decimal and all computation is done in decimal. (This version truncates results from divide and multiply operations.) There are two attributes of numbers, the length and the scale. The length is the total number of significant decimal digits in a number and the scale is the total number of decimal digits after the decimal point. For example: .000001 has a length of 6 and scale of 6. 1935.000 has a length of 7 and a scale of 3.
Am I understand this correctly?
