Dealing with exception in other method by using other method catch

Question

I need to see the result as a boolean result: true. But there's a catch I need to do it in a non-ordinary way.

import java.io.IOException; public class FlashLight { private Bulb bulb; private Battery[] batteries; public void on() { try { if (this.IsThereEnoughPower()) { this.bulb.setOn(true); for (Battery b : batteries) { b.setPower(b.getPower() - this.bulb.getBrightness()); } } } catch (IOException e) { System.out.println(e.getMessage()); this.setBatteries(new Battery[4]); } }

I need to catch the exception in method on() but i can only modify method: DetermineIfFlashlightCanBeTurnedOn

 public boolean DetermineIfFlashlightCanBeTurnedOn() throws IOException { return bulb != null && DetermineIfBatteriesAreInstalled() && IsThereEnoughPower(); } private boolean DetermineIfBatteriesAreInstalled() throws IOException { if (batteries.length < 4) { throw new IOException(Math.abs(-4 + batteries.length)); } for (Battery b : batteries) { if (b == null) { return false; } } return true; } private boolean IsThereEnoughPower() { for (Battery b : batteries) { if (b.getPower() < MIN_BATTERY_POWER) { return false; } } return true; } private static void testLatarki(String... args) { FlashLight flashlight = new Flashlight(); System.out.println(flashlight.DetermineIfFlashlightCanBeTurnedOn()); } }

Exception can be caught only in on() method. DetermineIfBatteriesAreInstalled() DetermineIfFlashlightCanBeTurnedOn must be signed as: throws IOException.

Well simply I need to properly compile DetermineIfFlashlightCanBeTurnedOn() method and catch the exception by using on() method in order to display "true" in console. — SpicyJam
– SpicyJam, Commented May 13, 2017 at 10:15

Community · Accepted Answer · 2017-05-23 10:31:13Z

You can use try{}catch(){} instead :

public boolean DetermineIfFlashlightCanBeTurnedOn() { try { return bulb != null && DetermineIfBatteriesAreInstalled() && IsThereEnoughPower(); } catch (Exception e) { //log your exception } return false; }

I forgot to tell you guys i can use try/catch blocks only in on() method

In this case you can use RuntimeException you don't need to use throws IOException in your method:

if (batteries.length < 4) { throw new RuntimeException(Math.abs(-4 + batteries.length)+""); }

So :

public boolean DetermineIfFlashlightCanBeTurnedOn() { //--not need to use throw throws IOException-------^ return bulb != null && DetermineIfBatteriesAreInstalled() && IsThereEnoughPower(); } private boolean DetermineIfBatteriesAreInstalled() { //--not need to use throw throws IOException------^ if (batteries.length < 4) { throw new RuntimeException(Math.abs(-4 + batteries.length) + ""); //----------^^ } for (Battery b : batteries) { if (b == null) { return false; } } return true; }

You can read more here Is there a way to throw an exception without adding the throws declaration?

I forgot to tell you guys i can use try/catch blocks only in on() method
I'm sorry, but it is unclear for me what your code does and what you are asking, even with your edit. I'm under the impression that you are not writing Java code, but Java-ized Objective-C or C++.
@M.leRutte the OP want to throw and catch the exception without using throw Exception in methods and use only try{}catch in on() method for that i suggest to use RuntimeException which not required to use throw Exception in method i hope this is what the OP need

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