why the following fails

Question

 Uri test = new Uri("http%3A%2F%2F100.100.1.1%3A8080");

An unhandled exception of type 'System.UriFormatException' occurred in System.dll

Additional information: Invalid URI: The format of the URI could not be determined.

Anyone know why I cannot pass in a URL encoded string to the constructor of Uri?

The encoding is meant for the querystring data, not the URL itself. — user447356
– user447356, Commented Dec 9, 2010 at 9:18

Jinesh Parekh · Accepted Answer · 2010-12-09 09:16:16Z

2

Do not escape it and try using http://100.100.1.1:8080.

answered Dec 9, 2010 at 9:16

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Comments

Henrik P. Hessel · Accepted Answer · 2010-12-09 09:18:03Z

The Uri Constructor requires the String to be a valid RFC2396 URI. There's this Uri.CheckSchemeName Method to check if your passed URI is valid.

DGH · Accepted Answer · 2010-12-09 09:16:41Z

0

Are you missing a % before the second 2F? Try passing the string through a URL un-encoder and make sure the result is what you expected.

answered Dec 9, 2010 at 9:16

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@user496949: Ah, ok, no problem.