Run a shell script multiple times at the same time [duplicate]

Question

I have a shell script called test.sh and a argument file called xaa in a directory. Location of the directory is /home/$USER/par

To run this script I am doing

cd /home/$USER/par

and then

./test.sh xaa

Until now the script works fine

Now I want to run the same test.sh script for different argument files like xab, xac, xad and so on at the same time.

what I want is to invoke test.sh

./test.sh xaa ./test.sh xab ./test.sh xac ./test.sh xad

all at the same time from one terminal only.

How can I achieve my requirement.

Inian · Accepted Answer · 2018-01-03 18:03:43Z

The simplest of the ways to do this would be to use the & notation to put them as background processes.

for arg in xaa xab xac xad; do ./test.sh "$arg" & done

You could also read up the parallelization techniques provided by xargs or GNU parallel for more computation intensive tasks.

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