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Question

I have a few structures I want to write to a binary file. They consist of integers from cstdint, for example uint64_t. Is there a way to write those to a binary file that does not involve me manually splitting them into arrays of char and using the fstream.write() functions?

What I've tried

My naive idea was that c++ would figure out that I have a file in binary mode and << would write the integers to that binary file. So I tried this:

#include <iostream> #include <fstream> #include <cstdint> using namespace std; int main() { fstream file; uint64_t myuint = 0xFFFF; file.open("test.bin", ios::app | ios::binary); file << myuint; file.close(); return 0; }

However, this wrote the string "65535" to the file.

Can I somehow tell the fstream to switch to binary mode, like how I can change the display format with << std::hex?

Failing all that above I'd need a function that turns arbitrary cstdint types into char arrays.

I'm not really concerned about endianness, as I'd use the same program to also read those (in a next step), so it would cancel out.

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  • See e.g. this answer Commented Mar 26, 2018 at 13:12

1 Answer 1

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19

Yes you can, this is what std::fstream::write is for:

#include <iostream> #include <fstream> #include <cstdint> int main() { std::fstream file; uint64_t myuint = 0xFFFF; file.open("test.bin", std::ios::app | std::ios::binary); file.write(reinterpret_cast<char*>(&myuint), sizeof(myuint)); // or with recent C++: reinterpret_cast<std::byte*> }
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6 Comments

That solves part of my problem. I'd like to be able to just use << with my custom fstream. Can I somehow overload << for all (or a set of) cstdint types? Like a template that accepts a predefined list of types?
Yes, just define a new type using std::fstream in its implementation, with a templated operator<<.
Yes, but can I tell that template to only accept, for example uint64_t, uint16_t and uint8_t, but not for example, std::string, or bool?
Yes. Yes you can.
why should i memcpy it to a char buffer?
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