I want to find a maximal interval in which an expression e is true for all x. A way to write such a formula should be: Exists d : ForAll x in (-d,d) . e and ForAll x not in (-d,d) . !e.
To get such a d, the formula f in Z3 (looking at the one above) could be the following:
from __future__ import division from z3 import * x = Real('x') delta = Real('d') s = Solver() e = And(1/10000*x**2 > 0, 1/5000*x**3 + -1/5000*x**2 < 0) f = ForAll(x, And(Implies(And(delta > 0, -delta < x, x < delta, x != 0), e), Implies(And(delta > 0, Or(x > delta, x < -delta), x != 0), Not(e)) ) ) s.add(Not(f)) s.check() print s.model() Which outputs [d = 1/4].
To check it, I set delta = RealVal('1/4'), drop the ForAll quantifier from f and I get x = 1/2. I replace delta with 1/2 and get 3/4, then 7/8 and so on. The bound should be 1. Can I get Z3 to output that immediately?