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May be this is silly question. I want to get rid of the fractional part of the Double number. But I cant do that. It shows the error that incompatible types. What to do?

Double to int conversion in one line....please help thanks

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    How about reading the documentation of the Double class? I am sure there is some method that will do the conversion. Commented Mar 23, 2011 at 11:04
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    You are talking about an error because of incompatible types. Then it's usually a good idea to show the code snippet you have tried. That helps giving better answers. Commented Mar 23, 2011 at 11:05
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    @Ingo i did googling and tried my best after that only I came to SO. Thanks for helping hands :) Commented Mar 23, 2011 at 11:19
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    docs.oracle.com/javase/7/docs/api/java/lang/… Commented Apr 18, 2014 at 16:00

5 Answers 5

Reset to default
186

If you really should use Double instead of double you even can get the int Value of Double by calling:

Double d = new Double(1.23); int i = d.intValue();

Else its already described by Peter Lawreys answer.

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sorry guys. I tried google and found double to int only. So then I came to disturb our Friends here :) That works. many thanks
This is a really bad idea in loops. It's much better to work with primitives.
docs.oracle.com/javase/7/docs/api/java/lang/…
why I did this and it gives me an error double cannot be dereferenced?
most likely you use a primitive type double and not Double, but you may want to ask that in your own question to provide more context.
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All other answer are correct, but remember that if you cast double to int you will loss decimal value.. so 2.9 double become 2 int.

You can use Math.round(double) function or simply do :

(int)(yourDoubleValue + 0.5d)
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Also worth noting that 2.999999999999997 becomes 2, which is undesired in most cases.
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double myDb = 12.3; int myInt = (int) myDb;

Result is: myInt = 12

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Daneos the question was about converting Double to int. Not double to int.
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try casting the value

double d = 1.2345; long l = (long) d;
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no it was not double it is a Double number. Thats why it shows the error i think.
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int average_in_int = ( (Double) Math.ceil( sum/count ) ).intValue();
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Math.ceil OR Math.floor is optional.

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