Using calloc() to create dynamic struct utmp array [duplicate]

Question

I'm attempting to create a dynamic array in C but I am a little confused on how to go about it. Firstly calloc() seems to be giving me strange results. I have some code as follows:

struct utmp userRec; printf("%d\n", sizeof(userRec)); //should print size of object structutmp * roster = calloc(1, sizeof(userRec)); printf("%d\n", sizeof(roster)); //should print total size of all objects in array printf("%d\n", sizeof(roster)/sizeof(roster[0])); //should print number of elements in array

Now the results of the prints are:

384 8 0

This output seems odd to me, since the first print seems okay. If that is the size of that particular object then fine, but then I thought the size of the array roster would be equal to that, since calloc was told to make room for one object with the same size as userRec. Finally the result of this one is also confusing. Shouldn't the result of this calculation be one? Since again I allocated space for one struct utmp, then the result should be that I have room for one struct utmp. Not zero. Any insight into why I'm getting these results would be appreciated!

Also one more question for if/when I finally get calloc() to work for me. I would like this array to be able to grow! I read that the realloc() function could be useful for this, but I am unsure. Does realloc() maintain the state of the array while adding more space? Also does free() return a pointer to the same memory block so I could call realloc() on it again?

Thanks for any answers!

roster is a pointer, not an array. You can't know the size of the underlying data with sizeof on a pointer. You allocated 1 struct utmp, so the size of the underlying data is 1*sizeof(struct utmp). — Dustin Nieffenegger
– Dustin Nieffenegger, Commented Feb 26, 2019 at 22:10
@Kody Richardson - there are several problems in your sample code. I tried to break them down in a response, but somebody cut me off at the knees with downvotes. BASIC PROBLEM: "sizeof(ptr)" doesn't return the size of a struct, array or object - it merely returns the #/bytes in a "pointer" (often "4", for a 32-bit CPU). No: "free()" does NOT return ANYTHING. Look here: man free. Finally, no: you can't "realloc()" memory you've already free()'ed. Q: Questions answered? — paulsm4
– paulsm4, Commented Feb 26, 2019 at 22:53
@DustinNieffenegger Thank you for pointing out my error with the roster!! — Kody Richardson
– Kody Richardson, Commented Feb 27, 2019 at 23:01

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Using calloc() to create dynamic struct utmp array [duplicate]

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