How to stop Makefile from expanding my shell output?

Question

By running this:

GITIGNORE_CONTENTS = $(shell while read -r line; do printf "$$line "; done < "$(.gitignore)") all: echo $(GITIGNORE_CONTENTS)

The contents of the variable GITIGNORE_CONTENTS are the expanded version of the ignore patterns on my .gitignore file, i.e., myfile.txt instead of *.txt

I am using this solution because none of the solution on the question Create a variable in a makefile by reading contents of another file work.

This solution works inside a make rule to print the file names, but not put them inside a variable:

all: while read -r line; do \ printf "$$line "; \ done < ".gitignore" echo $(GITIGNORE_CONTENTS)

Matt · Accepted Answer · 2019-04-05 05:16:44Z

This is an issue of shell's wildcard expansion, not of make's. Consider this,

GITIGNORE_CONTENTS:=$(shell cat .gitignore) .PHONY: all all: echo "$(GITIGNORE_CONTENTS)" # or alternatively: #/bin/echo $(GITIGNORE_CONTENTS)

Evandro Coan · Accepted Answer · 2019-04-05 23:20:03Z

By running this:

GITIGNORE_CONTENTS = $(shell while read -r line; do printf "$$line "; done < ".gitignore") all: echo "$(GITIGNORE_CONTENTS)"

With the following .gitignore file:

*.txt *.var # Comment *.xml *.html

It correctly outputs:

echo "*.txt *.var # Comment *.xml *.html " *.txt *.var # Comment *.xml *.html

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