Remove ./ from folder name in Python

Question

I am running the following code :

foldarz = [ f.path for f in os.scandir('.') if f.is_dir() ] print(foldarz)

This prints the folder name correctly, but with a prepended ".\". I don't want the ".\".

I know I can split the string etc, but I assume there's a better way without having to call another function.

I guess you can do: os.path.basename(f) instead of f.path. — Austin
– Austin, Commented Feb 5, 2020 at 17:36
f.path[2:] or f.path[3:]? Or f.name? ... docs.python.org/3/library/os.html#os.DirEntry.name — wwii
– wwii, Commented Feb 5, 2020 at 17:39

Austin · Accepted Answer · 2020-02-05 17:46:10Z

2

You can do os.path.basename:

foldarz = [os.path.basename(f) for f in os.scandir('.') if f.is_dir()]

edited Feb 5, 2020 at 17:46

answered Feb 5, 2020 at 17:40

Austin

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4 Comments

martineau Over a year ago

Looks like you're calling another function — something the OP wishes to avoid.

martineau Over a year ago

That seems to be the question (although that's not clear based on a comment made by OP).

Austin Over a year ago

I just noticed. How I read the question is like OP doesn't want to use string functions like split.

martineau Over a year ago

For the record, I personally think your answer's fine (because I don't know why calling a function is an issue).

Mike Mulhearn · Accepted Answer · 2020-02-05 17:48:21Z

os.path.normpath should help you remove the leading '.\' and give you the normalized path preferred by your operating system (think '/' instead of '\' depending upon user's OS)

foldarz = [os.path.normpath(f) for f in os.scandir('.') if f.is_dir()]

Mike Mulhearn · Accepted Answer · 2020-02-05 17:53:50Z

If you don't want to use other functions, you can also use os.DirEntry.name:

foldarz = [ f.name for f in os.scandir('.') if f.is_dir() ] print(foldarz)

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