I have the following code:
$final = [1 => 2]; $id = 1; $final[$id][0] = 3; The code seems to work fine, but I get this warning:
Warning: Cannot use a scalar value as an array in line X (the line with: $final[$id][0] = 3).
Can anyone tell me how to fix this?
You need to set$final[$id] to an array before adding elements to it. Intiialize it with either
$final[$id] = array(); $final[$id][0] = 3; $final[$id]['link'] = "/".$row['permalink']; $final[$id]['title'] = $row['title']; or
$final[$id] = array(0 => 3); $final[$id]['link'] = "/".$row['permalink']; $final[$id]['title'] = $row['title']; 
$final[$id][] = 3; and in the second to $final[$id] = array(3); :)
The reason is because somewhere you have first declared your variable with a normal integer or string and then later you are trying to turn it into an array.
The Other Issue I have seen on this is when nesting arrays this tends to throw the warning, consider the following:
$data = [ "rs" => null ] this above will work absolutely fine when used like:
$data["rs"] = 5; But the below will throw a warning ::
$data = [ "rs" => [ "rs1" => null; ] ] .. $data[rs][rs1] = 2; // this will throw the warning unless assigned to an array 
rs and rs1 on the last line. That makes them undefined constants, and so $data[rs] is not defined.Also make sure that you don't declare it an array and then try to assign something else to the array like a string, float, integer. I had that problem. If you do some echos of output I was seeing what I wanted the first time, but not after another pass of the same code.
