I have the following Bash code, which runs a C++ binary (./code) and stores the result:
#!/bin/bash output=$(./code /); read -ra arr -d '' <<<"$output" value=${arr[-1]} sum=$value+1.034 echo $sum I want it to be able to take the value of the variable sum, which is a number less than zero, ie 0.01357 and be able to add another floating point number to it, before outputting the result to the screen.
So the result should be 1.04757, but the output I am currently getting is:
0.01357+1.034 Bash doesn't support floating point arithmetics. You need another program doing the math for you.
Here are three examples using bc, awk or GNU datamash:
#!/bin/bash read -ra arr -d '' <<<"$(./code /)" # bc printf '%s + %s\n' "${arr[-1]}" "1.034" | bc # or awk #awk -v val="${arr[-1]}" 'BEGIN{print val + 1.034}' # or datamash #datamash sum 1 <<<$(printf '%s\n' "${arr[-1]}" "1.034") 
sum=$(awk -v val="${arr[-1]}" 'BEGIN{print val + 1.034}')awk with the -v option, e.g. one="0.5"; two="1.1"; sum=$(awk -v var1="$one" -v var2="$two" 'BEGIN{print var1 + var2}') or you could echo the values and use a pipe like sum=$(echo "0.5;1.1" | awk -F';' '{ print $1 + $2 }')
bcorawkor another program)