My operating system is windows 10.
I have a scheduled firebase function that I would like to run locally:
functions = require('firebase-functions') admin = require('firebase-admin') exports.myFunction = functions.pubsub.schedule('every 30 minutes').onRun((context) => { console.log('Hello World!') return null }) To run this function locally I run two commands(Answer taken from here):
firebase functions:shell myFunction() Can I execute this command in one line of code instead of two?
Separate out the function logic from the scheduling logic, then call the function directly with node:
function.js:
const functions = require('firebase-functions') const admin = require('firebase-admin') const foo = require('./foo') exports.myFunction = functions.pubsub.schedule('every 30 minutes').onRun(foo) foo.js:
module.exports = (context) => { console.log('Hello World!') return null } Call with node in one line:
node -e 'require("./foo")()' Note: You may need to manually supply the configuration/credentials in foo.js depending on what Firebase resources you are accessing since you are not running it in a Cloud environment when you call it directly.
