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I have a class in which i want to have a member variable for a method:

template<typename T> class ParamTest : public Action<T> { public: typedef void (*mixfunctype)(const T &t1, const T &t2, T &t3, double dParam); mixfunctype curFunc; void setMode(int iMode); ... protected: void test1(const T &t1, const T &t2, T &t3, double dParam); void test2(const T &t1, const T &t2, T &t3, double dParam); ... }

and in the code

template<typename T> void ParamTest<T>::setMode(int iMode) { if (iMode == 0) { curFunc = &test1; } else { curFunc = &test2; } }

But the compiler doesn't like this 

error: cannot convert ‘void (ParamTest<int>::*)(const int&, const int&, int&, double)’ to ‘ParamTest<int>::mixfunctype’ {aka ‘void (*)(const int&, const int&, int&, double)’} in assignment curFunc = &test1;

How should i declare the variable curFunc, and how should i assign a function to it, to have compilable code?

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    I created a live example for what you asked godbolt. You have to use: typedef void(ParamTest::*mixfunctype)(const T &t1, const T &t2, T &t3, double dParam); and in setMode you need to write curFunc = &ParamTest::test1. Commented May 12, 2020 at 11:58
  • Thanks that worked. For completeness, her is how to call the function from inside the class: (this->*curFunc)(tMother, tFather, tChild, dParam); Commented May 13, 2020 at 6:37
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