Python Redirect command output to log file [duplicate]

Question

I have written a Python code where I call below Scappy API:

sendp(packet, iface=adapter_name)

The code works fine but issue is that it prints below line on console where the program is executing as many times the above command is called:

Sent 1 packets. .

I need to suppress the console output so I tried:

old_stdout = sys.stdout sys.stdout = log_file_name

But then I get exception:

 sendp(packet, iface=adapter_name) File "C:\Python36\lib\site-packages\scapy\sendrecv.py", line 315, in sendp verbose=verbose, realtime=realtime, return_packets=return_packets) File "C:\Python36\lib\site-packages\scapy\sendrecv.py", line 289, in __gen_send print("\nSent %i packets." % n) AttributeError: 'str' object has no attribute 'write'

How can achieve the objective?

Does this answer your question? Redirect stdout to a file in Python? — Eno Gerguri
– Eno Gerguri, Commented Jun 24, 2020 at 13:42
You can just use verbose=0 on your send command to remove the logs... instead of doing a redirection :p — Cukic0d
– Cukic0d, Commented Jun 25, 2020 at 8:58

piertoni · Accepted Answer · 2020-06-24 13:53:32Z

You have this previously answered question if you want to redirect to file: Redirect stdout to a file in Python?

The following example for redirecting to a memory string (from python docs):

import io from contextlib import redirect_stdout f = io.StringIO() with redirect_stdout(f): help(pow) s = f.getvalue()

And the latter example (if you just want to suppress the sys.stdout), trying to understand how it works: print will try to access the write method of sys.stdout, so I will just replace it with a class that has a write method that does nothing.

>>> class R: ... def write(*args, **kwargs): ... pass >>> from contextlib import redirect_stdout >>> with redirect_stdout(R()): ... print('ciao')

I tried the same but now get on console '.................... ' instead of 'Sent 1 packets. .'
Not having your code I will suggest to try to use the context manager for the whole block of code. Seems that there is a print performed somewhere else.
Here the raw code output: >>> sendp(packet, iface='Intel(R) Ethernet Adapter') . Sent 1 packets.

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