Code:
def myFun(*args, **kwargs): print("args: ", args) print("kwargs: ", kwargs) args = input("Enter args: ") kwargs = input("Enter kwargs: ") myFun(args,kwargs) Output:
Enter args: 1,2,3,4 Enter kwargs: a=5,b=6,c=7 args: ('1,2,3,4', 'a=5,b=6,c=7') kwargs: {} Process finished with exit code 0 Here the expected output is:
args: (1,2,3,4) kwargs: {'a':5,'b':6,'c':7} I am getting the output not as the expected output.
You can use list and dictionary comprehension to parse the input of the users to be list to args and dictionary to kwargs and then unpacked them into myFun.
def myFun(*args, **kwargs): print("args: ", args) print("kwargs: ", kwargs) args = [int(i) if i.isdigit() else i for i in input("Enter args: ").split(",")] kwargs = {i.strip().split("=")[0]: int(i.strip().split("=")[1]) if i.strip().split("=")[1].isdigit() else i.strip().split("=")[1] for i in input("Enter kwargs: ").split(",")} myFun(*args, **kwargs) Entered
Enter args: 1,2,3,4 Enter kwargs: a=5,b=6,c=7 Output
args: (1, 2, 3, 4) kwargs: {'a': 5, 'b': 6, 'c': 7} So there are a few things here to note, you args are coming out as strings because they are being passed as strings. kwargs and args are variable names, but *args and **kwargs are not. So what you're trying to do is probably something like:
def parseArgs(inputString): return(inputString.split(',')) def parseKWargs(inputString): d = {} for element in parseArgs(inputString): current = element.split('=') d[current[0]] = current[1] return(d) def myFun(*args, **kwargs): print("args: ", args) print("kwargs: ", kwargs) args = parseArgs(input("Enter args: ")) kwargs = parseKWargs(input("Enter kwargs: ")) myFun(*args, **kwargs) kwargs needs to be a dictionary and "passed by reference" I believe is the correct way to word that. Hope this helps.
Thanks wjandrea for the good catches
args: (['1', '2', '3', '4'],) and kwargs: {'a': '5', 'b': '6', 'c': '7'}input as a variable name cause it shadows the builtin input(). Also argparse is the name of a standard library module, so you may want to use a different name to avoid confusion, but nbd.
kwargsstring to a dict, and no converting strings to ints.