C++ what's difference of param with const and without const in class constructor [duplicate]

Question

I have this code but compilation failed:

class TextBlock { public: TextBlock(std::string &s) { text = s; } private: std::string text; }; int main() { TextBlock tb("Hello"); std::cout<< tb[0] << std::endl ; }

why when the constructor is TextBlock(const std::string &s) the above code can compile success ?

sloppy speaking you need a string somewhere, a reference is just a reference. If the reference is const then the function is fine with taking a temporary because anyhow it wont be modified. Passing a temporary to a function that expects a non-const reference is pointless because you cannot observe the modifications, hence it makes sense that this is an error — 463035818_is_not_an_ai
– 463035818_is_not_an_ai, Commented Sep 2, 2020 at 12:57

ΦXocę 웃 Пepeúpa ツ · Accepted Answer · 2020-09-02 12:54:23Z

1

the constructor is specting a ref to a string do instead:

std::string x{"hello"}; TextBlock tb(x);

answered Sep 2, 2020 at 12:54

ΦXocę 웃 Пepeúpa ツ

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