I am trying to count the number of times a hex value appears in a file. The hex value is set in a variable.
Using the literal string "x01" returns the correct count:
grep -o $'\x01' ${fileName} | wc -l How can I use a variable in place of x01 ?
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1 Answer
Borrowing from Conversion hex string into ascii in bash command line
# single quote character in hex $ a='\x27' $ echo "a'b'c" | grep -o $(echo "$a" | xxd -r -p) ' ' $ echo "a'b'c" | grep -o $(echo "$a" | xxd -r -p) | wc -l 2 # you can also use just the number, \x prefix is optional $ echo "a'b'c" | grep -o $(echo '27' | xxd -r -p) | wc -l 2 # if PCRE is available $ echo "a'b'c" | grep -oP "$a" | wc -l 2 # with ripgrep (https://github.com/BurntSushi/ripgrep) $ echo "a'b'c" | rg -oc "$a" 2 2 Comments
Fiddlestiques
Thanks using your answer, I think this will work for me: grep -Fo $(echo "${delim1}" | xxd -r -p) ${filename} | wc -l
Sundeep
@Fiddlestiques that's because grep removes the newline before searching and adds it back when printing