How to fix the appearance of unexpected characters in string counts

Purely for fun ... you could do it all in two lines if you really wanted. :-)

String:

 s = 'ThiS is String with Upper and lower case Letters.' 

Ridiculousness:

chars = [i for i in s.lower() if i.isalpha()] print(*sorted({c: chars.count(c) for c in chars}.items(), key=lambda x: x[1], reverse=True), sep='\n') 

Output:

('t', 5) ('s', 5) ('e', 5) ('i', 4) ('r', 4) ('h', 2) ('n', 2) ('w', 2) ('p', 2) ('a', 2) ('l', 2) ('g', 1) ('u', 1) ('d', 1) ('o', 1) ('c', 1) 

So,You can remove spaces and dots from the input string.

s = 'ThiS is String with Upper and lower case Letters.' s=s.replace(" ","").replace(".","")# remove spaces and dots from the input string counts = {} for c in s.lower(): counts[c] = counts.get(c, 0) + 1 for c, n in sorted(counts.items()): print(c, n) 

[Output]:

a 2 c 1 d 1 e 5 g 1 h 2 i 4 l 2 n 2 o 1 p 2 r 4 s 5 t 5 u 1 w 2 

It looks like it's counting spaces and periods in the string as well. Replacing them with "" is an easy way to fix this.

import string from collections import Counter s = "".join(filter(lambda c: c in string.ascii_letters, s)) for c, count in Counter(s).items(): print(c, count) 

You can simply count them using str.count() with a simple check of isalpha():

s = 'ThiS is String with Upper and lower case Letters. 81' {char: s.count(char) for char in s.lower() if char.isalpha()} 

results in:

{'t': 4, 'h': 2, 'i': 4, 's': 3, 'r': 4, 'n': 2, 'g': 1, 'w': 2, 'u': 0, 'p': 2, 'e': 5, 'a': 2, 'd': 1, 'l': 1, 'o': 1, 'c': 1}