I'd like to send the two overloaded fun()s to one template that handles them plus their arguments. This is my attempt so far:
#include <vector> #include <iostream> using namespace std; class Demo {}; template<typename Function, typename... Args> void call(Function func(Args...), Args &&...args) { func(forward<Args>(args)...); // execute function with args } void fun(int first, int second, int third) { cout << "fun with ints\n"; } void fun(Demo &&dem1, Demo &&dem2) // adding overload causes the ambiguity { cout << "fun with Demos\n"; } int main() { call(fun, 1, 2, 3); call(fun, Demo{}, Demo{}); } The compiler complains that it can't find a matching function for the calls in main():
main.cc: In function ‘int main()’: main.cc:27:22: error: no matching function for call to ‘call(<unresolved overloaded function type>, int, int, int)’ 27 | call(fun, 1, 2, 3); | ^ main.cc:10:6: note: candidate: ‘template<class Function, class ... Args> void call(Function (*)(Args ...), Args&& ...)’ 10 | void call(Function func(Args...), Args &&...args) | ^~~~ main.cc:10:6: note: template argument deduction/substitution failed: main.cc:27:22: note: couldn’t deduce template parameter ‘Function’ 27 | call(fun, 1, 2, 3); | ^ main.cc:29:29: error: no matching function for call to ‘call(<unresolved overloaded function type>, Demo, Demo)’ 29 | call(fun, Demo{}, Demo{}); | ^ main.cc:10:6: note: candidate: ‘template<class Function, class ... Args> void call(Function (*)(Args ...), Args&& ...)’ 10 | void call(Function func(Args...), Args &&...args) | ^~~~ main.cc:10:6: note: template argument deduction/substitution failed: main.cc:29:29: note: couldn’t deduce template parameter ‘Function’ 29 | call(fun, Demo{}, Demo{}); | Any ideas to find a solution to this puzzle would be highly appreciated! (the solution at C++ overloaded function as template argument did not solve my problem because I cannot change the way that call() is called in main() )
