Convert ASCII number to ASCII Character in C

You can assign int to char directly.

int a = 65; char c = a; printf("%c", c); 

In fact this will also work.

printf("%c", a); // assuming a is in valid range 

If i is the int, then

char c = i; 

makes it a char. You might want to add a check that the value is <128 if it comes from an untrusted source. This is best done with isascii from <ctype.h>, if available on your system (see @Steve Jessop's comment to this answer).

If the number is stored in a string (which it would be if typed by a user), you can use atoi() to convert it to an integer.

An integer can be assigned directly to a character. A character is different mostly just because how it is interpreted and used.

char c = atoi("61"); 

char A; printf("ASCII value of %c = %d", c, c); 

In this program, the user is asked to enter a character. The character is stored in variable c. When %d format string is used, 65 (the ASCII value of A) is displayed. When %c format string is used, A itself is displayed.

Output: ASCII value of A = 65

#include <stdio.h> #include <cs50.h> int d; int main(void){ string a = get_string("enter your word: "); int i = 0; while(a[i] != '\0'){ printf("%i ", a[i]); i++; } printf("\n"); }