So what i understand is that if for example i have an int a = 49 and want to find out the ASCII equivalent to it, all i need to do is:
int a = 49; System.out.println((char)a); which has the Output: 1.
But how can i do this reversed? So lets say i have int a = 1 and i want the output to be 49?
I have already tried stuff like:
int a = 1; System.out.println ((char)a); But the output here is "." instead of 49.
This:
int a = 49; System.out.println((char)a); gives you the char whose internal value is 49, which is to say the unicode character '1'. There is no numerical conversion going on, it's just two ways to look at the same number.
In this:
int a = 1; System.out.println((char)a); you get the char whose internal value is 1, which is a unicode control character (ctrl/A, which probably won't be printed in any useful way). There is nothing there that can magically come up with the value 49.
If you had the character '1' then it's easy:
int a = '1'; System.out.println(a); but this is practically the same as your first case; '1' and 49 are the same value.
1ascharwhich means'1'.ato move from'0'characteraamount of times. For instance'0' + 0would return index of'0'.'0' + 1would return index of'1'. All you need to do with that index is convert it back tochar. So you can write something likeint a = 1; char ch = (char)('0'+a);.char ch = Character.forDigit(a, 10);.