Replace all instances of a character in a 2d numpy array [duplicate]

Question

I have a Numpy array like this:

 [[ a, b, c] [ d, d, e] [ d, f, g ]]

How would I go about replacing every instance of char d in this 2d array while keeping the shape of the array? Assuming temp is our 2d array, I tried this but it did not work:

for i in range(len(temp)): temp[i].replace('d','')

Please provide a minimal reproducible example. Don't be lazy. — juanpa.arrivillaga
– juanpa.arrivillaga, Commented Apr 28, 2021 at 21:32
@juanpa.arrivillaga I think what OP gave there is an MRE already. The attempted code didn’t run for the obvious reason, but IMHO, that’s good enough. — Quang Hoang
– Quang Hoang, Commented Apr 28, 2021 at 21:35

Quang Hoang · Accepted Answer · 2021-04-28 21:32:28Z

1

Assuming temp as a numpy array, try update with indexing

temp[temp=='d'] = ''

answered Apr 28, 2021 at 21:32

Quang Hoang

151k11 gold badges64 silver badges86 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

James · Accepted Answer · 2021-04-28 21:35:36Z

You can just use slice it on a boolean index and set the value.

import numpy as np x = np.array([[ 'a', 'b', 'c'], [ 'd', 'd', 'e'], [ 'd', 'f', 'g' ]] ) x[x=='d'] = 'z'

Collectives™ on Stack Overflow

Replace all instances of a character in a 2d numpy array [duplicate]

2 Answers 2

Comments

Comments

Linked

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Linked

Related