Composing a string in script shell [duplicate]

Question

So I'm trying to compose a string using script shell

#!/bin/sh blNumber=1111619832 echo '*'$blNumber+='*.xlsx'

I expect the output to be: *1111619832*.xlsx but as a result I get: *+=*.xlsx

Btw I tried to figure out why so I tried this code

#!/bin/sh blNumber=1111619832 output="*${blNumber}"

and whenever I add something after *${blNumber} it get concatenated at the begging of the string

@HamaLAHLOU : Removed bash tag, because the question is not bash-related. — user1934428
– user1934428, Commented Jul 2, 2021 at 7:34
@HamaLAHLOU : Just use b1Numer="$b1Number.xlsx", or more general, b1Numer="${b1Number}.xlsx" — user1934428
– user1934428, Commented Jul 2, 2021 at 7:35
@HamzaLAHOU : You can - with few exceptions, which don't apply here - not modify a variable inside another statement. You have to first write a statement which changes the variable, and then you can use it in i.e. an echo. — user1934428
– user1934428, Commented Jul 2, 2021 at 7:37

wjandrea · Accepted Answer · 2021-07-01 16:07:26Z

1

Why are you using += in the first place?

$ echo '*'$blNumber'*.xlsx' *1111619832*.xlsx

Or put it inside double-quotes. It's best practice to quote all variables anyway.

$ echo "*$blNumber*.xlsx" *1111619832*.xlsx

answered Jul 1, 2021 at 16:07

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4 Comments

I tried your solution but ut's not working. the output : *.xlsx19832

the link above solved the issue on notepad++