How to identify previous view controller in navigation stack

Here's the implementation of the accepted answer:

- (UIViewController *)backViewController { NSInteger numberOfViewControllers = self.navigationController.viewControllers.count; if (numberOfViewControllers < 2) return nil; else return [self.navigationController.viewControllers objectAtIndex:numberOfViewControllers - 2]; } 

- (UIViewController *)backViewController { NSInteger myIndex = [self.navigationController.viewControllers indexOfObject:self]; if ( myIndex != 0 && myIndex != NSNotFound ) { return [self.navigationController.viewControllers objectAtIndex:myIndex-1]; } else { return nil; } } 

A more general implementation of the accepted answer:

- (UIViewController *)backViewController { NSArray * stack = self.navigationController.viewControllers; for (int i=stack.count-1; i > 0; --i) if (stack[i] == self) return stack[i-1]; return nil; } 

This will return the correct "back view controller" regardless of where the current class is on the navigation stack.

Swift implementation of tjklemz code as an extension:

extension UIViewController { func backViewController() -> UIViewController? { if let stack = self.navigationController?.viewControllers { for(var i=stack.count-1;i>0;--i) { if(stack[i] == self) { return stack[i-1] } } } return nil } } 

Here's a modifed version of Prabhu Beeman's Swift code that adapts it to support Swift 3:

extension UIViewController { func backViewController() -> UIViewController? { if let stack = self.navigationController?.viewControllers { for i in (1..<stack.count).reverse() { if(stack[i] == self) { return stack[i-1] } } } return nil } } 

As a UINavigationController extension:

extension UINavigationController { func previousViewController() -> UIViewController? { guard viewControllers.count > 1 else { return nil } return viewControllers[viewControllers.count - 2] } } 

Access the n-2 element of the viewControllers property to access the parent view controller.

Once you have that instance, you can check its type by logging what comes out of the NSStringFromClass() function. Or you could keep some static const identifier string in controllers A and B, and a getter function that prints out the string.

Swift implementation of @tjklemz code:

var backViewController : UIViewController? { var stack = self.navigationController!.viewControllers as Array for (var i = stack.count-1 ; i > 0; --i) { if (stack[i] as UIViewController == self) { return stack[i-1] as? UIViewController } } return nil } 

Use the navigationController method to retrieve it. See documentation on Apple's site.

navigationController A parent or ancestor that is a navigation controller. (read-only)

@property(nonatomic, readonly, retain) UINavigationController *navigationController

Discussion Only returns a navigation controller if the view controller is in its stack. This property is nil if a navigation controller cannot be found.

Availability Available in iOS 2.0 and later.

Find the previous view controller is simple.

In your case, i.e., you are in C and you need B, [self.navigationController.viewControllers lastObject] is what you want.

For A, since A is the root view controller, you can just replace lastObject with firstObject to obtain.

Because dead horses enjoy being beaten :)

- (UIViewController *)previousViewController { NSArray *vcStack = self.navigationController.viewControllers; NSInteger selfIdx = [vcStack indexOfObject:self]; if (vcStack.count < 2 || selfIdx == NSNotFound) { return nil; } return (UIViewController *)[vcStack objectAtIndex:selfIdx - 1]; } 

A more succinct Swift impementation:

extension UIViewController { var previousViewController: UIViewController? { guard let nav = self.navigationController, let myIdx = nav.viewControllers.index(of: self) else { return nil } return myIdx == 0 ? nil : nav.viewControllers[myIdx-1] } } 

Implementation for Swift 2.2 - Add this in an UIViewController extension. Safe in the sense it will return nil if the viewcontroller is the rootvc or not in a navigationcontroller.

var previousViewController: UIViewController? { guard let viewControllers = navigationController?.viewControllers else { return nil } var previous: UIViewController? for vc in viewControllers{ if vc == self { break } previous = vc } return previous } 

With Swift using guard.

extension UIViewController { func getPreviousViewController() -> UIViewController? { guard let _ = self.navigationController else { return nil } guard let viewControllers = self.navigationController?.viewControllers else { return nil } guard viewControllers.count >= 2 else { return nil } return viewControllers[viewControllers.count - 2] } } 

My extension, swift 3

extension UIViewController { var previousViewController: UIViewController? { guard let controllers = navigationController?.viewControllers, controllers.count > 1 else { return nil } switch controllers.count { case 2: return controllers.first default: return controllers.dropLast(2).first } } } 

for swift 3 you can do this:

var backtoViewController:UIViewController! for viewController in (self.navigationController?.viewControllers)!.reversed() { if viewController is NameOfMyDestinationViewController { backtoViewController = viewController } } self.navigationController!.popToViewController(backtoViewController, animated: true) 

You only need replace "NameOfMyDestinationViewController" by viewController that you want to return.