I am new to hibernate and spring in general. And trying to create a food delivery application. I've two classes as below Restaurant and CustomerOrder mapped with oneToOne Association.
CustomerOrder.java
@Entity @Table @Getter @Setter public class CustomerOrder { @Id Long id; @OneToOne(cascade = CascadeType.ALL) @JoinColumn(name = "restaurant_id", nullable = false) Restaurant restaurant; } Restaurant.java
@Entity @Table @Getter @Setter public class Restaurant { @Id Long id; String name; String address; @OneToOne(mappedBy = "restaurant") CustomerOrder customerOrder; } i have pre populated postgres database. I am using import.sql for it, which loads the values in the database at the boot time of the app.
import.sql
insert into customer("id", "location", "name") values (1, 'cg road', 'kunal'); insert into customer("id", "location", "name") values (2, 'delux avenue', 'tirth'); insert into customer("id", "location", "name") values (3, 'sp road', 'parth'); insert into restaurant("id", "address", "name") values(1, 'divine circle', 'grand thaker'); insert into restaurant("id", "address", "name") values(2, 'alpha mall', 'honest'); insert into restaurant("id", "address", "name") values(3, 'acropolish mall', 'starbucks'); application.properties
spring.datasource.url=jdbc:postgresql://localhost:5432/zomato1?createDatabaseIfNotExist=true spring.datasource.username= spring.datasource.password= spring.jpa.hibernate.ddl-auto=create-drop spring.jpa.show-sql=true spring.jpa.properties.hibernate.dialect=org.hibernate.dialect.PostgreSQLDialect spring.jpa.properties.hibernate.format_sql=true when i do the post request to create the new entry for CustomerOrder with the body
{ "id" : 1, "restaurant_id" : 2 } I am getting the above error.