How do I terminate an asyncio loop in these conditions?

Question

I am creating a python code that does the following:

1 - creates an asynchronous function called "nums" than prints random numbers from 0 to 10 every 2 seconds. 2 - execute a function that prints "hello world" every 5 seconds. 3 - if the function "nums" prints 1 or 3, break the loop and end the program.

The thing is, it's not breaking out of the loop. What I am supposed to do? Thank you.

import asyncio import random async def nums(): while True: x = print(random.randint(0, 10)) await asyncio.sleep(2) if x == 1 or x == 3: break async def world(): while True: print("hello world") await asyncio.sleep(5) async def main(): while True: await asyncio.wait([nums(), world()]) if __name__ == '__main__': asyncio.run(main())

Have you done any debug printing? The print function returns nothing, so x will always be None. — Tim Roberts
– Tim Roberts, Commented Oct 17, 2022 at 20:55

Andrej Kesely · Accepted Answer · 2022-10-17 20:58:34Z

You can use return_when=asyncio.FIRST_COMPLETED parameter in asyncio.wait:

import asyncio import random async def nums(): while True: x = random.randint(0, 10) print(x) if x in {1, 3} break await asyncio.sleep(2) async def world(): while True: print("hello world") await asyncio.sleep(5) async def main(): task1 = asyncio.create_task(nums()) task2 = asyncio.create_task(world()) await asyncio.wait({task1, task2}, return_when=asyncio.FIRST_COMPLETED) if __name__ == "__main__": asyncio.run(main())

Prints (for example):

5 hello world 6 6 hello world 1 <program ends here>

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