In java how to get substring from a string till a character c?

The accepted answer is correct but it doesn't tell you how to use it. This is how you use indexOf and substring functions together.

String filename = "abc.def.ghi"; // full file name int iend = filename.indexOf("."); //this finds the first occurrence of "." //in string thus giving you the index of where it is in the string // Now iend can be -1, if lets say the string had no "." at all in it i.e. no "." is found. //So check and account for it. String subString; if (iend != -1) { subString= filename.substring(0 , iend); //this will give abc } 

You can just split the string..

public String[] split(String regex) 

Note that java.lang.String.split uses delimiter's regular expression value. Basically like this...

String filename = "abc.def.ghi"; // full file name String[] parts = filename.split("\\."); // String array, each element is text between dots String beforeFirstDot = parts[0]; // Text before the first dot 

Of course, this is split into multiple lines for clairity. It could be written as

String beforeFirstDot = filename.split("\\.")[0]; 

If your project already uses commons-lang, StringUtils provide a nice method for this purpose:

String filename = "abc.def.ghi"; String start = StringUtils.substringBefore(filename, "."); // returns "abc" 

see javadoc [2.6] [3.1]

or you may try something like

"abc.def.ghi".substring(0,"abc.def.ghi".indexOf(c)-1);

I tried something like this,

String str = "abc.def.ghi"; String strBeforeFirstDot = str.substring(0, str.indexOf('.')); // strBeforeFirstDot = "abc" 

I tried for my example, to extract all char before @ sign in email to extract and provide a username.

How about using regex?

String firstWord = filename.replaceAll("\\..*","") 

This replaces everything from the first dot to the end with "" (ie it clears it, leaving you with what you want)

Here's a test:

System.out.println("abc.def.hij".replaceAll("\\..*", ""); 

Output:

abc 

In java.lang.String you get some methods like indexOf(): which returns you first index of a char/string. and lstIndexOf: which returns you the last index of String/char

From Java Doc:

 public int indexOf(int ch) public int indexOf(String str) 

Returns the index within this string of the first occurrence of the specified character.

public void getStrings() { String params = "abc.def.ghi"; String s1, s2, s3; s1 = params.substring(0, params.indexOf(".")); params = params.substring(params.indexOf(".") + 1); s2 = params.substring(0, params.indexOf(".")); params = params.substring(params.indexOf(".") + 1, params.length()); s3 = params; } 

the solution

s1="abc" s2="def" s3="ghi"

IF you have more than 3 String , so then it will look exactly like s2

Here is code which returns a substring from a String until any of a given list of characters:

/** * Return a substring of the given original string until the first appearance * of any of the given characters. * <p> * e.g. Original "ab&cd-ef&gh" * 1. Separators {'&', '-'} * Result: "ab" * 2. Separators {'~', '-'} * Result: "ab&cd" * 3. Separators {'~', '='} * Result: "ab&cd-ef&gh" * * @param original the original string * @param characters the separators until the substring to be considered * @return the substring or the original string of no separator exists */ public static String substringFirstOf(String original, List<Character> characters) { return characters.stream() .map(original::indexOf) .filter(min -> min > 0) .reduce(Integer::min) .map(position -> original.substring(0, position)) .orElse(original); } 

This could help:

public static String getCorporateID(String fileName) { String corporateId = null; try { corporateId = fileName.substring(0, fileName.indexOf("_")); // System.out.println(new Date() + ": " + "Corporate: // "+corporateId); return corporateId; } catch (Exception e) { corporateId = null; e.printStackTrace(); } return corporateId; } 

 private String getTextBefore(final String wholeString, String before){ final int indexOf = wholeString.indexOf(before); if(indexOf != -1){ return wholeString.substring(0, indexOf); } return wholeString; }