Most efficient way to create an array based on other arrays [duplicate]

Question

I have an array with varying number of objects like so:

const arrayA = [ {name: n, value: v} {name: n, value: v} ... {name: n, value: v} ]

I have another array with n number of numbers:

const arrayB = [1, 13, 28]

Length of arrayB is less or equal than of arrayA but never higher.

Now I need to create another array - arrayC: Array<boolean> = []. The length of arrayC should be equal to length of arrayA

arrayA.length == arrayC.length

with all false boolean values apart from those with index of every value from arrayB

I could probably achieve this with bunch of forEach and/or for loops but what I want to know is what would be the most efficient and not resource consuming way to get it.

Ry- · Accepted Answer · 2025-01-13 23:02:58Z

Create an initial all-false array by making an array with the right length and setting all its elements to the same value:

const arrayC = Array(arrayA.length).fill(false);

Then set the elements by index:

for (const i of arrayB) { arrayC[i] = true; }

Collectives™ on Stack Overflow

Most efficient way to create an array based on other arrays [duplicate]

1 Answer 1

Comments

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Linked

Related