I need a regex to match something like
"4f0f30500be4443126002034"
and
"4f0f30500be4443126002034>4f0f31310be4443126005578"
but not like
"4f0f30500be4443126002034>4f0f31310be4443126005578>4f0f31310be4443126005579"
- Can you provide some more details about what should and shouldn't match? Why does the 3rd one not match? Because it consists of 3 numbers?mikej– mikej2012-01-13 17:06:10 +00:00Commented Jan 13, 2012 at 17:06
- Yes. I want to only match the string of two numbers, not three.Red– Red2012-01-13 17:08:37 +00:00Commented Jan 13, 2012 at 17:08
- 1Well, the string of one or two numbers, not three. To be specific.Red– Red2012-01-13 17:09:07 +00:00Commented Jan 13, 2012 at 17:09
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3 Answers
Try:
^[\da-f]{24}(>[\da-f]{24})?$ [\da-f]{24} is exactly 24 characters consisting only of 0-9, a-f. The whole pattern is one such number optionally followed by a > and a second such number.
Comments
I think you want something like:
/^[0-9a-f]{24}(>[0-9a-f]{24})?$/ That matches 24 characters in the 0-9a-f range (which matches your first string) followed by zero or one strings starting with a >, followed by 24 characters in the 0-9a-f range (which matches your second string). Here's a RegexPal for this regex.
Comments
Don't need a regex.
str = "4f0f30500be4443126002034>4f0f31310be4443126005578"
match = str.count('>') < 2
match will be set to true for matches where there are 1 or 0 '>' in the string. Otherwise match is set to false.
