Trying to exit a method, using return, but doesn't actually return anything

Question

I'm using return EXIT_SUCCESS to exit a void function. However I get a flag that says my method should not return a value.

The code works fine, but is there a better way to exit a method by using a return or something else?

Daniel · Accepted Answer · 2012-02-12 02:17:14Z

7

To add to the other answers, you can always return from a void function with return;

answered Feb 12, 2012 at 2:17

Daniel

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Comments

Rayfleck · Accepted Answer · 2012-02-12 01:49:10Z

Redefine the method as

-(int)myMethod;

Then you can return EXIT_SUCCESS.

Is any code calling this method and expecting a value?

fdh · Accepted Answer · 2012-02-12 01:53:33Z

I don't think you understand how functions work. When you specify the prototype asvoid you are saying the function won't return anything. You are then contradicting the prototype by trying to return something. Change the prototype to -(int)function to return EXIT_SUCCESS. If you do not want to return something, but want to still check if it was successful you could pass in a pointer to the function: -(void)functionReturnValue:int* returnValue. Make the function set returnValue to EXIT_SUCCESS on successful completion and have the calling function check returnValue.

You are talking about functions but your examples show methods.
@Till I wasn't aware there was a difference. What's the difference between functions and methods?

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