Linked Questions

In C++11 and C++14, why do I need constexpr in the following snippet: class Foo { static constexpr double X = 0.75; }; whereas this one produces a compiler error: class Foo { static const ...

I am a bit confused by the static in-class initialization of a const member. For example, in the code below: #include <iostream> struct Foo { const static int n = 42; }; // const int Foo::...

==> See the full snippet code and compilation on coliru. I have a LiteralType class filling constexpr requirements: struct MyString { constexpr MyString(char const* p, int s) : ptr(p), sz(s) {} ...

This work: template<typename T> struct Something { static constexpr const char* str = "int"; }; int main() { std::cout << Something<int>::str << std::endl; } But it doesn't: ...

I am looking for a portable one line replacement for the #define in the following code. The replacement should hide the word APPLE in the namespace of the Foo object. class Foo { public: #define ...

The following code produces an undefined reference to 'Test::color'. #include <iostream> struct Color{ int r,g,b; }; void printColor(Color color) { //printing color } class Test { ...

If I want to use some convenience stuff like make_array I have no chance to declare my array first and later make the definition as done in "earlier" times because the type of my var is not available ...

Here's the minimum code: #include <iostream> #include <complex> using namespace std; class Test { static const double dt = 0.1; public: void func(); }; void Test::func() { ...

below is my code: // types.h template <typename T> struct type_to_char {}; template <> struct type_to_char<char> { static constexpr char str[] = "baz"; }; // main.cpp #include &...

I'm working on a kernel and I want to make my static data member constexpr so I can have its values in an enum class. However, if I do so I get an undefined reference error. It only seems to work if I ...

This is my code, a.cpp struct int2 { int x, y; }; struct Foo{ static constexpr int bar1 = 1; static constexpr int2 bar2 = {1, 2}; }; int foo1(){ return Foo::bar1; // this is ok for ...

I'm trying to use a class to group all the parameters of a template data structure, in particular an intrusive AVL tree. The user would do something like this: struct MyEntry { MyEntry *parent; ...

I got this compile time string comparison from another thread using constexpr and C++11 (http://stackoverflow.com/questions/5721813/compile-time-assert-for-string-equality). It works with constant ...

Consider the following code: #include <iostream> template<class T> struct foo {}; template<> struct foo<int> { static constexpr char value[] = "abcde"; }; ...

Compiling with -std=c++14 the following code: #include <memory> class A { public: static constexpr int c = 0; std::shared_ptr<int> b; A() { b = std::make_shared&...