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$\begingroup$ What is the function of the abs in the code above? Won't the flipping of the labels be equally as random without abs? $\endgroup$

Matthew Brett
– Matthew Brett

2020-05-18 11:56:07 +00:00
Commented May 18, 2020 at 11:56
1

$\begingroup$ @MatthewBrett in this case I think the idea is to precisely control which data points lie on which side of 0. My intuition is that if you randomly flip the signs but the signs aren't already evenly distributed, you might not get as good of a result. $\endgroup$

shadowtalker
– shadowtalker

2022-09-02 14:36:43 +00:00
Commented Sep 2, 2022 at 14:36

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