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Dec 14, 2011 at 14:02 answer added steffen timeline score: 3
Dec 13, 2011 at 20:41 comment added Farzad @whuber: you are right but i need some more accurate, at least some thing that is function of $r$
Dec 13, 2011 at 20:23 comment added whuber You mean the obvious bounds of $2^{-N}$ and $1$ will be fine?
Dec 13, 2011 at 20:16 comment added Farzad @whuber: any upper or lower bound is quite good for me.
Dec 13, 2011 at 20:15 comment added Farzad @jbowman: you are right.
Dec 13, 2011 at 6:22 history edited whuber CC BY-SA 3.0
added 2 characters in body; edited tags
Dec 13, 2011 at 6:20 comment added whuber What kind of answer are you looking for? Even in the case $N=1$ there is no closed form solution (except possibly for special values of $r/\sigma$).
Dec 13, 2011 at 6:15 history edited whuber CC BY-SA 3.0
added 5 characters in body; edited title
S Dec 12, 2011 at 21:26 history suggested Innuo CC BY-SA 3.0
Orthant is the correct term that suits the content of the question
Dec 12, 2011 at 21:24 review Suggested edits
S Dec 12, 2011 at 21:26
Dec 12, 2011 at 21:04 comment added jbowman I assume you meant $\Vert \mathbf{x} - \mathbf{y} \Vert$ in your last line of math?
Dec 12, 2011 at 20:50 history asked Farzad CC BY-SA 3.0