Skip to main content

You are not logged in. Your edit will be placed in a queue until it is peer reviewed.

We welcome edits that make the post easier to understand and more valuable for readers. Because community members review edits, please try to make the post substantially better than how you found it, for example, by fixing grammar or adding additional resources and hyperlinks.

Required fields*

6
  • 109
    $\begingroup$ Thanks, guys. I'm glad this came together well; this is actually a good example of how you can learn things on CV by answering questions, as well as asking & reading others' answers: I knew this information beforehand, but not quite well enough that I could just write it out cold. So I actually spent some time going through my old texts to figure out how to organize the material & put it forward clearly, & in the process solidified these ideas for myself. $\endgroup$ Commented Jun 22, 2012 at 18:18
  • 6
    $\begingroup$ @gung Thanks for this explanation, it is one of the clearest descriptions of GLMs in general that I have come across. $\endgroup$ Commented Sep 27, 2012 at 23:35
  • $\begingroup$ @whuber "When the response variable is not normally distributed (for example, if your response variable is binary) this approach [standard OLS] may no longer be valid." I'm sorry to bother you (again!) with this, but I find this bit confusing. I understand that there are no unconditional distributional assumptions on the dependent variable in OLS. Does this quote mean to imply that since the response is so wildly non-normal (i.e. a binary variable) that its conditional distribution given $X$ (and hence the distribution of the residuals) cannot possibly approach normality? $\endgroup$ Commented Mar 27, 2014 at 9:45
  • 9
    $\begingroup$ @landroni, you may want to ask a new question for this. In short, if your response is binary, the conditional distribution of Y given X=xi cannot possibly approach normality; it will always be binomial. The distribution of the raw residuals will also never approach normality. They will always be pi & (1-pi). The sampling distribution of the conditional mean of Y given X=xi (ie, pi) will approach normality, though. $\endgroup$ Commented Mar 27, 2014 at 13:41
  • 2
    $\begingroup$ I share somewhat of landroni's concern: after all, a normally distributed outcome non-normally distributed residuals, and a non-normally distributed outcome may have normally distributed residuals. The issue with the outcome seems to be less about its distribution per se, than its range. $\endgroup$ Commented Jul 23, 2014 at 20:47