Timeline for Clarification on ANOVA mechanism
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 18, 2020 at 18:31 | comment | added | Robert Long | No worries, you're welcome. I feel your pain. This happens to me all the time. I use simulation in many of my answers and regularly find a typo that changes small details (and sometimes large details) in what follows :/ LOL to your last sentence :D | |
| Oct 18, 2020 at 18:08 | comment | added | BruceET | Typo. Thanks for spotting that. If I correct it, changes would propagate as follows: MS(Gp) = 51,5, MSA = 14.5, F=3.55, P=0.043. May change it all later, but it may cause extra confusion to make changes immediately. // As it stands: an unintended demo of sensitivity of ANOVA to heteroscedasticity. | |
| Oct 18, 2020 at 17:43 | comment | added | Robert Long | Great answer (+1), just wondering if x3 = rnorm(10, 22, 4) should have a standard deviation of 3 rather than 4 ? | |
| Oct 18, 2020 at 17:40 | comment | added | BruceET | 2 is numerator DF for F-statistic (3 gps - 1 = 2); 27 is denominator DF (3(10 reps - 1)=27). // The simple formulas I illustrated for MSA and MS(Gp) are for a balanced design. Slightly messier if different numbers of replications in 3 groups. // Added stripchart to show exact values of the ten replications in each group. | |
| Oct 18, 2020 at 17:39 | history | edited | BruceET | CC BY-SA 4.0 | added 211 characters in body |
| Oct 18, 2020 at 11:42 | vote | accept | Nemo | ||
| Oct 18, 2020 at 11:41 | comment | added | Nemo | Fantastic answer! At first glance, one would assume the three groups x1, x2 and x3 came from the same population (given their similar means and variances), but then ANOVA rejected that assumption! Would you mind clarifying what the two numbers (2, 27) mean? Thanks. | |
| Oct 18, 2020 at 8:40 | history | answered | BruceET | CC BY-SA 4.0 |