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I want my all cells have horizontally and vertically centered except second column. I want my second column only vertically centered, but the alignment is on the left.

My attempt:

\documentclass[a4paper]{book} \usepackage{blindtext} \usepackage{amssymb} \usepackage{amsmath} \usepackage{amsfonts} \usepackage{amsthm} \begin{document} \begin{center} \begin{tabular}{|c|c|p{4cm}|} \hline No. & $f(t)$ & $F(s)$\\ \hline 1. & Fungsi tangga konstan, $f(t)=1$ & $$\frac 1s;\, s>0$$\\ \hline 2. & Fungsi identitas, $f(t)=t$ & $$\frac 1{s^2};\, s>0$$\\ \hline 3. & Fungsi eksponensial, $f(t)=1$ & $$\frac 1s;\, s>0$$\\ \hline 4. & Fungsi tangga konstan, $f(t)=e^{-\omega t}$ & $$\frac 1{s+\omega};\, s>0$$\\ \hline \end{tabular} \end{center} \end{document}

Can you help me? I've seen my possible duplicate, but seems like there is an error when I'm using \usepackage{ragged2e}. And I want the width to fit the text length naturally. For example, the first column has a smaller width.

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  • 1
    \begin{tabular}{|c|l|m{4cm}|} should result in the desired alignment. Commented Aug 6, 2020 at 10:37
  • @leandriis it's error. Commented Aug 6, 2020 at 10:45
  • 1
    Did you load the array package? The m column type is only available when the array package is loaded. Commented Aug 6, 2020 at 11:06

2 Answers 2

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To vertically centre cells contents, you can use the cellspace package, which ensures a minimal vertical spacing at the top and bottom of cells in columns with specifier prefixed with the letter S (unfortunately already used by siunitx), or any letter you want with the loading option column=:

\documentclass[a4paper]{book} \usepackage{blindtext} \usepackage{array} \usepackage[column=O]{cellspace} \setlength{\cellspacetoplimit}{5pt} \setlength{\cellspacebottomlimit}{4pt} \usepackage{amssymb} \usepackage{amsmath} \usepackage{amsthm} \begin{document} \begin{center} \begin{tabular}{|c|l|>{$\displaystyle}Oc<{$}|} \hline No. & \multicolumn{1}{c|}{$f(t)$} & F(s)\\ \hline 1. & Fungsi tangga konstan, $f(t)=1$ & \frac 1s;\, s>0 \\ \hline 2. & Fungsi identitas, $f(t)=t$ & \frac 1{s²};\, s>0 \\ \hline 3. & Fungsi eksponensial, $f(t)=1$ & \frac 1s;\, s>0 \\ \hline 4. & Fungsi tangga konstan, $f(t)=e^{-ωt}$ & \frac 1{s+ω};\, s>0 \\ \hline \end{tabular} \end{center} \end{document}

enter image description here

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  • Thank you very much for the answer, i really appreciate it. Commented Aug 6, 2020 at 11:08
  • Hi, can i have a last question please? My last problem is the header of the table. I want them all to centered but won't affect the other cells. (the second column of the header still on the left) Commented Aug 6, 2020 at 11:58
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    Use \multicolumn{1}{|c|}{$f(t)$} for the head of the 2nd column. Commented Aug 6, 2020 at 12:01
  • @Bernard: I think that there is a slight mistake in your comment. It should be \multicolumn{1}{c|}{$f(t)$}. Commented Aug 6, 2020 at 15:31
  • @F.Pantigny: You're right. One of my many lapsus calami… Commented Aug 6, 2020 at 15:51
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Centering both for horz and vert -- I think you will make out the difference and be able to do the rest-- if not please revert

enter image description here

\begin{tabular}{ | >{\centering\arraybackslash}m{1in}% instead of "p" is "m" | >{\centering\arraybackslash}m{1in}% instead of "p" is "m" | >{\centering\arraybackslash}m{1in}% instead of "p" is "m" |} \hline No. & $f(t)$ & $F(s)$\\ \hline 1. & Fungsi tangga konstan, $f(t)=1$ & $$\frac 1s;\, s>0$$\\ \hline 2. & Fungsi identitas, $f(t)=t$ & $$\frac 1{s^2};\, s>0$$\\ \hline 3. & Fungsi eksponensial, $f(t)=1$ & $$\frac 1s;\, s>0$$\\ \hline 4. & Fungsi tangga konstan, $f(t)=e^{-\omega t}$ & $$\frac 1{s+\omega};\, s>0$$\\ \hline \end{tabular}
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  • Thank you very much for the answer, i really appreciate it. Commented Aug 6, 2020 at 11:08

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