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I have been having a look at this for a while but I haven't found any answer yet.

I've got a curl command to send a HTTP POST request to a server, then I have created a script called "tmg.sh" which looks like the next one:

#! /bin/bash echo "There you go:" sleep 3s curl "http://tmg.xunta.gal/consulta-tarxeta?blah_blah_blah&numero=$1" echo "Thanks!"

Right then, so when I write the next command on the terminal:

chmode u+x ./tmg.sh

Because for some reason even in root account if I don't do this, it returns: bash: ./tmg.sh: Permission denied, but anyway let's go on, after I have done that, when I write the following:

./tmg.sh NUMBER_GOES_HERE

That number is the variable, then I got this answer:

There you go: <html code not relevant> <div class="infoContido"><p>Non hai ningunha recarga para o n&uacute;mero de tarxeta introducido.</p></div> <html code not relevant> Thanks!

Right, here comes my question, how can I get just a part of the whole HTML code? I mean, I just want a part of the website, something like this:

Non hai ningunha recarga para o número de tarxeta introducido.

Also, I'd like to notice that as I get a full page, there are plenty of <p>, <div>... Is that possible, if it is, how should I edit my script to get just this part?

Thank you so much and have a lovely day!

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    Please provide a working example, with the exact command you are running, the exact web-site address, the output, and the expected result. Please use a public website which everyone can access for the example. Commented Jun 18, 2017 at 12:13
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    This is a very simple task with an Xpath parser, but which one to use depends on your platform. Also, your terminology is off; you want to "extract" the text from an HTML "element". Google that (maybe add "div" and "class") and you should get plenty of hits. (No obvious duplicates on this site; this isn't really a Unix problem, anyway.) Commented Jun 18, 2017 at 13:54

3 Answers 3

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You do not explain how the text you want should be identified.

If you just want the text, try with links instead:

#! /bin/bash echo "There you go:" sleep 3s links -dump "http://tmg.xunta.gal/consulta-tarxeta?blah_blah_blah&numero=$1" echo "Thanks!"

If the line identifier is "infoContido" this might be the solution:

#! /bin/bash echo "There you go:" sleep 3s curl "http://tmg.xunta.gal/consulta-tarxeta?blah_blah_blah&numero=$1" | grep infoContido | cut -d\> -f2 echo "Thanks!"
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If the class of the div object you want will always be infoContido, you can use pup with a command like:

curl "http://tmg.xunta.gal/consulta-tarxeta?blah_blah_blah&numero=$1" | pup "div.infoContido"
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Send the curl output to a new file. For example in the above mentioned case. 

curl "http://tmg.xunta.gal/consulta-tarxeta?blah_blah_blah&numero=$1" | tee -a /var/tmp/mycurl

Now all you need to do is grep your line from this new file.

cat /var/tmp/mycurl | grep Non hai ningunha recarga para o número de tarxeta introducido.
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  • Until something puts a line break between any of the words, which has no effect on the HTML but completely breaks your "parser". Commented Jun 19, 2017 at 17:52
  • With your logic, a simple echo would be enough .... echo "Non hai ningunha recarga para o número de tarxeta introducido." OP wants to "grep" what is enclosed between <p> and </p>. Does not know what text it is inside those tags.... Commented Jun 19, 2017 at 20:22

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