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pass command line arguments through to the ls command

edited Jan 9, 2019 at 23:02

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Sometimes an alias isn't powerful enough to easily do what you want, so here's a way without using them.

In some file that is sourced when your shell starts (e.g. .bashrc), add the following function:

ls () { echo "Hello world!" command ls "$@" }

Unlike an alias, a function can recurse. That's why command ls is used instead of ls; it tells your shell to use the actual ls instead of the function you've just defined.

Sometimes an alias isn't powerful enough to easily do what you want, so here's a way without using them.

In some file that is sourced when your shell starts (e.g. .bashrc), add the following function:

ls () { echo "Hello world!" command ls }

Unlike an alias, a function can recurse. That's why command ls is used instead of ls; it tells your shell to use the actual ls instead of the function you've just defined.

Sometimes an alias isn't powerful enough to easily do what you want, so here's a way without using them.

In some file that is sourced when your shell starts (e.g. .bashrc), add the following function:

ls () { echo "Hello world!" command ls "$@" }

Unlike an alias, a function can recurse. That's why command ls is used instead of ls; it tells your shell to use the actual ls instead of the function you've just defined.

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answered Jan 26, 2015 at 0:44

undergroundmonorail

Sometimes an alias isn't powerful enough to easily do what you want, so here's a way without using them.

In some file that is sourced when your shell starts (e.g. .bashrc), add the following function:

ls () { echo "Hello world!" command ls }

Unlike an alias, a function can recurse. That's why command ls is used instead of ls; it tells your shell to use the actual ls instead of the function you've just defined.