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edited Apr 13, 2017 at 12:36

As @terdon's answer answer but without the sed:

awk '{ for(i=1;i<=NF;i+=2){ if ($i<0) $(i+1)*=-1; $i = ""; } print }'

As @terdon's answer but without the sed:

awk '{ for(i=1;i<=NF;i+=2){ if ($i<0) $(i+1)*=-1; $i = ""; } print }'

As @terdon's answer but without the sed:

awk '{ for(i=1;i<=NF;i+=2){ if ($i<0) $(i+1)*=-1; $i = ""; } print }'

answered Jun 21, 2015 at 16:03

As @terdon's answer but without the sed:

awk '{ for(i=1;i<=NF;i+=2){ if ($i<0) $(i+1)*=-1; $i = ""; } print }'