Timeline for Get the real, apparent size of a folder
Current License: CC BY-SA 3.0
16 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Feb 10, 2016 at 16:21 | vote | accept | newBee | ||
| S Feb 10, 2016 at 16:14 | history | edited | newBee | Question is about size file and directory , not disk-usage. | |
| S Feb 10, 2016 at 16:14 | history | suggested | GAD3R | Question is about size file and directory , not disk-usage. | |
| Feb 10, 2016 at 16:13 | review | Suggested edits | |||
| S Feb 10, 2016 at 16:14 | |||||
| Feb 10, 2016 at 16:11 | answer | added | RealSkeptic | timeline score: 2 | |
| Feb 10, 2016 at 15:59 | history | edited | newBee | CC BY-SA 3.0 | added 309 characters in body |
| Feb 10, 2016 at 15:54 | comment | added | newBee | @RealSkeptic 20 folders and around 10k files. The hierarchy is 3 levels deep.Updated the question to give you a rough example | |
| Feb 10, 2016 at 15:45 | comment | added | RealSkeptic | How many files are in that folder? Could your WinSCP be counting just the contents of the files and ignoring the actual folders? | |
| Feb 10, 2016 at 15:20 | comment | added | MelBurslan | find is recursive from the top level directory name you give, unless it is explicitly told the depth. Does this folder contain a lot of so-called sparse files by any chance ? Like database table containers and such ? | |
| Feb 10, 2016 at 15:08 | history | edited | newBee | CC BY-SA 3.0 | added hint that it needs to include subfolders/has to be recursive |
| Feb 10, 2016 at 15:07 | comment | added | newBee | Despite running very very long it always returns 0. Maybe should have mentioned that the folder contains subfolders, so it has to be recursive. | |
| Feb 10, 2016 at 14:59 | comment | added | MelBurslan | try running this command and see what it gives you a=0;find some_dir_name_here -type f | xargs ls -l| while read line; do b=$(echo $line|awk '{print $5}'); (( a=$a+$b ));done; echo "Size is " $a | |
| Feb 10, 2016 at 14:51 | comment | added | newBee | without the modifier it returns a folder size of approx. 1G. Although this might be the actual "size on disk" this is not the "real file size". | |
| Feb 10, 2016 at 14:48 | comment | added | MelBurslan | try du -sk or du -sh without the --apparent-size modifier. | |
| Feb 10, 2016 at 14:37 | review | First posts | |||
| Feb 10, 2016 at 14:49 | |||||
| Feb 10, 2016 at 14:33 | history | asked | newBee | CC BY-SA 3.0 |