If the list of positional parameters is:

$ set -- 0wer 1wdfg 2erty 333 4ffff 5s5s5 

Then this will print the arguments without the last:

$ echo "${@:1:$#-1}" 0wer 1wdfg 2erty 333 4ffff 

Of course, the parameters could be set to that as well:

$ set -- "${@:1:$#-1}" $ echo $@ 0wer 1wdfg 2erty 333 4ffff 

That works in bash version 2.0 or above.

For other simpler shells, you need a (somewhat tricky) loop to remove the last parameter:

unset b; for a; do set -- "$@" "$b"; shift; b="$a"; done 

If the list of positional parameters is:

$ set -- 0wer 1wdfg 2erty 333 4ffff 5s5s5 

Then this will print the arguments without the last:

$ echo "${@:1:$#-1}" 0wer 1wdfg 2erty 333 4ffff 

Of course, the parameters could be set to that as well:

$ set -- "${@:1:$#-1}" $ echo $@ 0wer 1wdfg 2erty 333 4ffff 

That works in bash version 2.0 or above.

For other simpler shells, you need a (somewhat tricky) loop to remove the last parameter:

unset b; for a; do set -- "$@" ${b+"$b"}; shift; b="$a"; done